Excess work done on call (perhaps wrong Dfun type) with scipy.integrate.odeint

2 min read 07-10-2024
Excess work done on call (perhaps wrong Dfun type) with scipy.integrate.odeint


Overdoing It: Understanding Excess Work in scipy.integrate.odeint

The Problem: You're using scipy.integrate.odeint to solve an ordinary differential equation (ODE), but you notice your code is taking longer than expected. You suspect it's doing unnecessary work due to a mismatch between the function type (Dfun) and the solver's requirements.

Scenario:

Let's say you have a simple ODE:

def f(y, t):
  return -y 

y0 = 1
t = np.linspace(0, 5, 100)

Now, using odeint:

import numpy as np
from scipy.integrate import odeint

sol = odeint(f, y0, t)

The Code:

The core issue lies in the f function, which we're passing to odeint. In this case, f is a Python function taking two arguments: y (the dependent variable) and t (time). However, odeint expects a function that returns a vector of derivatives – the rate of change of each variable with respect to time.

Analysis:

Our f function only returns a single value (-y), not a vector. This misalignment forces odeint to repeatedly call f for each individual component of the solution vector, effectively creating a loop within the solver. This leads to significant overhead, especially if the system has many variables or the solution requires a high number of time steps.

Solutions:

  1. Vectorize Your Function: The most direct fix is to modify f to return a vector of derivatives. Since we have a single variable in this case, the output remains a scalar:
def f(y, t):
  return np.array([-y]) 

# Rest of the code remains the same
  1. Use a Different Solver: If you need more fine-grained control or want to optimize for specific types of ODEs, consider using a different solver from the scipy.integrate module. Options like solve_ivp provide greater flexibility in defining the function type (fun), allowing you to pass it in a vectorized or non-vectorized form depending on your needs.

Example:

from scipy.integrate import solve_ivp

def f(t, y):
  return -y

sol = solve_ivp(f, (0, 5), [y0], dense_output=True)

Here, solve_ivp expects f to accept t as the first argument and y as the second, which is the standard convention in many numerical solvers.

Conclusion:

By understanding the expected function type for odeint and ensuring your function returns the appropriate vector of derivatives, you can significantly reduce the amount of unnecessary work performed by the solver. This optimization leads to faster execution times and a more efficient solution process. Remember to always carefully check the documentation of the solver you are using to avoid such potential pitfalls.

Additional Resources: